(2n^2/4n^2-3)=1/2

Solution for (2n^2/4n^2-3)=1/2 equation:

(2n^2/4n^2-3)=1/2

We move all terms to the left:

(2n^2/4n^2-3)-(1/2)=0


Domain of the equation: 4n^2-3)!=0

n∈R


We add all the numbers together, and all the variables

(2n^2/4n^2-3)-(+1/2)=0

We get rid of parentheses

2n^2/4n^2-3-1/2=0

We calculate fractions


(-4n^2)/8n^2+4n^2/8n^2-3=0

We multiply all the terms by the denominator


(-4n^2)+4n^2-3*8n^2=0

We add all the numbers together, and all the variables

4n^2+(-4n^2)-3*8n^2=0

Wy multiply elements

4n^2+(-4n^2)-24n^2=0

We get rid of parentheses

4n^2-4n^2-24n^2=0

We add all the numbers together, and all the variables

-24n^2=0

a = -24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-24)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{-48}=0$